3(x-1)+16=8(2x+6)-3x-1

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Solution for 3(x-1)+16=8(2x+6)-3x-1 equation: 



3(x-1)+16=8(2x+6)-3x-1

We move all terms to the left:

3(x-1)+16-(8(2x+6)-3x-1)=0

We multiply parentheses

3x-(8(2x+6)-3x-1)-3+16=0



We calculate terms in parentheses: -(8(2x+6)-3x-1), so:

8(2x+6)-3x-1

We add all the numbers together, and all the variables

-3x+8(2x+6)-1

We multiply parentheses

-3x+16x+48-1

We add all the numbers together, and all the variables

13x+47

Back to the equation:

-(13x+47)



We add all the numbers together, and all the variables

3x-(13x+47)+13=0

We get rid of parentheses

3x-13x-47+13=0

We add all the numbers together, and all the variables

-10x-34=0

We move all terms containing x to the left, all other terms to the right

-10x=34

x=34/-10

x=-3+2/5

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