3(x-1)+1=2(x-1)+x

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Solution for 3(x-1)+1=2(x-1)+x equation: 



3(x-1)+1=2(x-1)+x

We move all terms to the left:

3(x-1)+1-(2(x-1)+x)=0

We multiply parentheses

3x-(2(x-1)+x)-3+1=0



We calculate terms in parentheses: -(2(x-1)+x), so:

2(x-1)+x

We add all the numbers together, and all the variables

x+2(x-1)

We multiply parentheses

x+2x-2

We add all the numbers together, and all the variables

3x-2

Back to the equation:

-(3x-2)



We add all the numbers together, and all the variables

3x-(3x-2)-2=0

We get rid of parentheses

3x-3x+2-2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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