3(x-1)+1=5(x+2)-8

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Solution for 3(x-1)+1=5(x+2)-8 equation:



3(x-1)+1=5(x+2)-8
We move all terms to the left:
3(x-1)+1-(5(x+2)-8)=0
We multiply parentheses
3x-(5(x+2)-8)-3+1=0
We calculate terms in parentheses: -(5(x+2)-8), so:
5(x+2)-8
We multiply parentheses
5x+10-8
We add all the numbers together, and all the variables
5x+2
Back to the equation:
-(5x+2)
We add all the numbers together, and all the variables
3x-(5x+2)-2=0
We get rid of parentheses
3x-5x-2-2=0
We add all the numbers together, and all the variables
-2x-4=0
We move all terms containing x to the left, all other terms to the right
-2x=4
x=4/-2
x=-2

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