3(x-1)+2(3-2x)=6(x+4)

Solution for 3(x-1)+2(3-2x)=6(x+4) equation:

3(x-1)+2(3-2x)=6(x+4)

We move all terms to the left:

3(x-1)+2(3-2x)-(6(x+4))=0

We add all the numbers together, and all the variables

3(x-1)+2(-2x+3)-(6(x+4))=0

We multiply parentheses

3x-4x-(6(x+4))-3+6=0


We calculate terms in parentheses: -(6(x+4)), so:

6(x+4)

We multiply parentheses

6x+24

Back to the equation:

-(6x+24)


We add all the numbers together, and all the variables

-1x-(6x+24)+3=0

We get rid of parentheses

-1x-6x-24+3=0

We add all the numbers together, and all the variables

-7x-21=0

We move all terms containing x to the left, all other terms to the right

-7x=21

x=21/-7

x=-3