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3(x-1)+2(3x+6)-2=6x-3+2x+10
We move all terms to the left:
3(x-1)+2(3x+6)-2-(6x-3+2x+10)=0
We add all the numbers together, and all the variables
3(x-1)+2(3x+6)-(8x+7)-2=0
We multiply parentheses
3x+6x-(8x+7)-3+12-2=0
We get rid of parentheses
3x+6x-8x-7-3+12-2=0
We add all the numbers together, and all the variables
x=0
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