3(x-1)+2(4-x)=x-5(x+3)

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Solution for 3(x-1)+2(4-x)=x-5(x+3) equation: 



3(x-1)+2(4-x)=x-5(x+3)

We move all terms to the left:

3(x-1)+2(4-x)-(x-5(x+3))=0

We add all the numbers together, and all the variables

3(x-1)+2(-1x+4)-(x-5(x+3))=0

We multiply parentheses

3x-2x-(x-5(x+3))-3+8=0



We calculate terms in parentheses: -(x-5(x+3)), so:

x-5(x+3)

We multiply parentheses

x-5x-15

We add all the numbers together, and all the variables

-4x-15

Back to the equation:

-(-4x-15)



We add all the numbers together, and all the variables

x-(-4x-15)+5=0

We get rid of parentheses

x+4x+15+5=0

We add all the numbers together, and all the variables

5x+20=0

We move all terms containing x to the left, all other terms to the right

5x=-20

x=-20/5

x=-4

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