3(x-1)+2(4x-4)=-12+6(x-1)

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Solution for 3(x-1)+2(4x-4)=-12+6(x-1) equation: 



3(x-1)+2(4x-4)=-12+6(x-1)

We move all terms to the left:

3(x-1)+2(4x-4)-(-12+6(x-1))=0

We multiply parentheses

3x+8x-(-12+6(x-1))-3-8=0



We calculate terms in parentheses: -(-12+6(x-1)), so:

-12+6(x-1)

determiningTheFunctionDomain
6(x-1)-12

We multiply parentheses

6x-6-12

We add all the numbers together, and all the variables

6x-18

Back to the equation:

-(6x-18)



We add all the numbers together, and all the variables

11x-(6x-18)-11=0

We get rid of parentheses

11x-6x+18-11=0

We add all the numbers together, and all the variables

5x+7=0

We move all terms containing x to the left, all other terms to the right

5x=-7

x=-7/5

x=-1+2/5

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