3(x-1)+2(x-1)+(x-1)=6

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Solution for 3(x-1)+2(x-1)+(x-1)=6 equation: 



3(x-1)+2(x-1)+(x-1)=6

We move all terms to the left:

3(x-1)+2(x-1)+(x-1)-(6)=0

We multiply parentheses

3x+2x+(x-1)-3-2-6=0

We get rid of parentheses

3x+2x+x-1-3-2-6=0

We add all the numbers together, and all the variables

6x-12=0

We move all terms containing x to the left, all other terms to the right

6x=12

x=12/6

x=2

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