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3(x-1)+2=6x-3(x+1)
We move all terms to the left:
3(x-1)+2-(6x-3(x+1))=0
We multiply parentheses
3x-(6x-3(x+1))-3+2=0
We calculate terms in parentheses: -(6x-3(x+1)), so:We add all the numbers together, and all the variables
6x-3(x+1)
We multiply parentheses
6x-3x-3
We add all the numbers together, and all the variables
3x-3
Back to the equation:
-(3x-3)
3x-(3x-3)-1=0
We get rid of parentheses
3x-3x+3-1=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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