3(x-1)+2x=3x+(-x)+-9

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Solution for 3(x-1)+2x=3x+(-x)+-9 equation:



3(x-1)+2x=3x+(-x)+-9
We move all terms to the left:
3(x-1)+2x-(3x+(-x)+-9)=0
We add all the numbers together, and all the variables
3(x-1)+2x-(3x+(-1x)+-9)=0
We add all the numbers together, and all the variables
2x+3(x-1)-(3x+(-1x)+-9)=0
We use the square of the difference formula
2x+3(x-1)-(3x+(-1x)-9)=0
We multiply parentheses
2x+3x-(3x+(-1x)-9)-3=0
We calculate terms in parentheses: -(3x+(-1x)-9), so:
3x+(-1x)-9
We get rid of parentheses
3x-1x-9
We add all the numbers together, and all the variables
2x-9
Back to the equation:
-(2x-9)
We add all the numbers together, and all the variables
5x-(2x-9)-3=0
We get rid of parentheses
5x-2x+9-3=0
We add all the numbers together, and all the variables
3x+6=0
We move all terms containing x to the left, all other terms to the right
3x=-6
x=-6/3
x=-2

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