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3(x-1)+2x=5(x-3)
We move all terms to the left:
3(x-1)+2x-(5(x-3))=0
We add all the numbers together, and all the variables
2x+3(x-1)-(5(x-3))=0
We multiply parentheses
2x+3x-(5(x-3))-3=0
We calculate terms in parentheses: -(5(x-3)), so:We add all the numbers together, and all the variables
5(x-3)
We multiply parentheses
5x-15
Back to the equation:
-(5x-15)
5x-(5x-15)-3=0
We get rid of parentheses
5x-5x+15-3=0
We add all the numbers together, and all the variables
12!=0
There is no solution for this equation
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