3(x-1)+3=9-2(x+1)

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Solution for 3(x-1)+3=9-2(x+1) equation: 



3(x-1)+3=9-2(x+1)

We move all terms to the left:

3(x-1)+3-(9-2(x+1))=0

We multiply parentheses

3x-(9-2(x+1))-3+3=0



We calculate terms in parentheses: -(9-2(x+1)), so:

9-2(x+1)

determiningTheFunctionDomain
-2(x+1)+9

We multiply parentheses

-2x-2+9

We add all the numbers together, and all the variables

-2x+7

Back to the equation:

-(-2x+7)



We add all the numbers together, and all the variables

3x-(-2x+7)=0

We get rid of parentheses

3x+2x-7=0

We add all the numbers together, and all the variables

5x-7=0

We move all terms containing x to the left, all other terms to the right

5x=7

x=7/5

x=1+2/5

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