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3(x-1)+5=11+2(x-1)
We move all terms to the left:
3(x-1)+5-(11+2(x-1))=0
We multiply parentheses
3x-(11+2(x-1))-3+5=0
We calculate terms in parentheses: -(11+2(x-1)), so:We add all the numbers together, and all the variables
11+2(x-1)
determiningTheFunctionDomain 2(x-1)+11
We multiply parentheses
2x-2+11
We add all the numbers together, and all the variables
2x+9
Back to the equation:
-(2x+9)
3x-(2x+9)+2=0
We get rid of parentheses
3x-2x-9+2=0
We add all the numbers together, and all the variables
x-7=0
We move all terms containing x to the left, all other terms to the right
x=7
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