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3(x-1)+5=4(x-3)-2(2x-3)
We move all terms to the left:
3(x-1)+5-(4(x-3)-2(2x-3))=0
We multiply parentheses
3x-(4(x-3)-2(2x-3))-3+5=0
We calculate terms in parentheses: -(4(x-3)-2(2x-3)), so:We add all the numbers together, and all the variables
4(x-3)-2(2x-3)
We multiply parentheses
4x-4x-12+6
We add all the numbers together, and all the variables
-6
Back to the equation:
-(-6)
3x+8=0
We move all terms containing x to the left, all other terms to the right
3x=-8
x=-8/3
x=-2+2/3
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