3(x-1)+5=6(x+2)

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Solution for 3(x-1)+5=6(x+2) equation: 



3(x-1)+5=6(x+2)

We move all terms to the left:

3(x-1)+5-(6(x+2))=0

We multiply parentheses

3x-(6(x+2))-3+5=0



We calculate terms in parentheses: -(6(x+2)), so:

6(x+2)

We multiply parentheses

6x+12

Back to the equation:

-(6x+12)



We add all the numbers together, and all the variables

3x-(6x+12)+2=0

We get rid of parentheses

3x-6x-12+2=0

We add all the numbers together, and all the variables

-3x-10=0

We move all terms containing x to the left, all other terms to the right

-3x=10

x=10/-3

x=-3+1/3

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