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3(x-1)+7x=4x+2-3(2-x)
We move all terms to the left:
3(x-1)+7x-(4x+2-3(2-x))=0
We add all the numbers together, and all the variables
3(x-1)+7x-(4x+2-3(-1x+2))=0
We add all the numbers together, and all the variables
7x+3(x-1)-(4x+2-3(-1x+2))=0
We multiply parentheses
7x+3x-(4x+2-3(-1x+2))-3=0
We calculate terms in parentheses: -(4x+2-3(-1x+2)), so:We add all the numbers together, and all the variables
4x+2-3(-1x+2)
determiningTheFunctionDomain 4x-3(-1x+2)+2
We multiply parentheses
4x+3x-6+2
We add all the numbers together, and all the variables
7x-4
Back to the equation:
-(7x-4)
10x-(7x-4)-3=0
We get rid of parentheses
10x-7x+4-3=0
We add all the numbers together, and all the variables
3x+1=0
We move all terms containing x to the left, all other terms to the right
3x=-1
x=-1/3
x=-1/3
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