3(x-1)-(x+2)=x+2(x-1)

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Solution for 3(x-1)-(x+2)=x+2(x-1) equation: 



3(x-1)-(x+2)=x+2(x-1)

We move all terms to the left:

3(x-1)-(x+2)-(x+2(x-1))=0

We multiply parentheses

3x-(x+2)-(x+2(x-1))-3=0

We get rid of parentheses

3x-x-(x+2(x-1))-2-3=0



We calculate terms in parentheses: -(x+2(x-1)), so:

x+2(x-1)

We multiply parentheses

x+2x-2

We add all the numbers together, and all the variables

3x-2

Back to the equation:

-(3x-2)



We add all the numbers together, and all the variables

2x-(3x-2)-5=0

We get rid of parentheses

2x-3x+2-5=0

We add all the numbers together, and all the variables

-1x-3=0

We move all terms containing x to the left, all other terms to the right

-x=3

x=3/-1

x=-3

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