3(x-1)-(x+4)=x+5(x-1)

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Solution for 3(x-1)-(x+4)=x+5(x-1) equation: 



3(x-1)-(x+4)=x+5(x-1)

We move all terms to the left:

3(x-1)-(x+4)-(x+5(x-1))=0

We multiply parentheses

3x-(x+4)-(x+5(x-1))-3=0

We get rid of parentheses

3x-x-(x+5(x-1))-4-3=0



We calculate terms in parentheses: -(x+5(x-1)), so:

x+5(x-1)

We multiply parentheses

x+5x-5

We add all the numbers together, and all the variables

6x-5

Back to the equation:

-(6x-5)



We add all the numbers together, and all the variables

2x-(6x-5)-7=0

We get rid of parentheses

2x-6x+5-7=0

We add all the numbers together, and all the variables

-4x-2=0

We move all terms containing x to the left, all other terms to the right

-4x=2

x=2/-4

x=-1/2

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