3(x-1)-(x+4)=x+5(x-1)

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Solution for 3(x-1)-(x+4)=x+5(x-1) equation:



3(x-1)-(x+4)=x+5(x-1)
We move all terms to the left:
3(x-1)-(x+4)-(x+5(x-1))=0
We multiply parentheses
3x-(x+4)-(x+5(x-1))-3=0
We get rid of parentheses
3x-x-(x+5(x-1))-4-3=0
We calculate terms in parentheses: -(x+5(x-1)), so:
x+5(x-1)
We multiply parentheses
x+5x-5
We add all the numbers together, and all the variables
6x-5
Back to the equation:
-(6x-5)
We add all the numbers together, and all the variables
2x-(6x-5)-7=0
We get rid of parentheses
2x-6x+5-7=0
We add all the numbers together, and all the variables
-4x-2=0
We move all terms containing x to the left, all other terms to the right
-4x=2
x=2/-4
x=-1/2

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