3(x-1)-(x-9)+(x-3)=(x+4)+(x+2)

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Solution for 3(x-1)-(x-9)+(x-3)=(x+4)+(x+2) equation: 



3(x-1)-(x-9)+(x-3)=(x+4)+(x+2)

We move all terms to the left:

3(x-1)-(x-9)+(x-3)-((x+4)+(x+2))=0

We multiply parentheses

3x-(x-9)+(x-3)-((x+4)+(x+2))-3=0

We get rid of parentheses

3x-x+x-((x+4)+(x+2))+9-3-3=0



We calculate terms in parentheses: -((x+4)+(x+2)), so:

(x+4)+(x+2)

We get rid of parentheses

x+x+4+2

We add all the numbers together, and all the variables

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

3x-(2x+6)+3=0

We get rid of parentheses

3x-2x-6+3=0

We add all the numbers together, and all the variables

x-3=0

We move all terms containing x to the left, all other terms to the right

x=3

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