3(x-1)-1=2(x+2)-3

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Solution for 3(x-1)-1=2(x+2)-3 equation: 



3(x-1)-1=2(x+2)-3

We move all terms to the left:

3(x-1)-1-(2(x+2)-3)=0

We multiply parentheses

3x-(2(x+2)-3)-3-1=0



We calculate terms in parentheses: -(2(x+2)-3), so:

2(x+2)-3

We multiply parentheses

2x+4-3

We add all the numbers together, and all the variables

2x+1

Back to the equation:

-(2x+1)



We add all the numbers together, and all the variables

3x-(2x+1)-4=0

We get rid of parentheses

3x-2x-1-4=0

We add all the numbers together, and all the variables

x-5=0

We move all terms containing x to the left, all other terms to the right

x=5

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