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3(x-1)-1=5-5(x+5)
We move all terms to the left:
3(x-1)-1-(5-5(x+5))=0
We multiply parentheses
3x-(5-5(x+5))-3-1=0
We calculate terms in parentheses: -(5-5(x+5)), so:We add all the numbers together, and all the variables
5-5(x+5)
determiningTheFunctionDomain -5(x+5)+5
We multiply parentheses
-5x-25+5
We add all the numbers together, and all the variables
-5x-20
Back to the equation:
-(-5x-20)
3x-(-5x-20)-4=0
We get rid of parentheses
3x+5x+20-4=0
We add all the numbers together, and all the variables
8x+16=0
We move all terms containing x to the left, all other terms to the right
8x=-16
x=-16/8
x=-2
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