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3(x-1)-2(2x+1)=8(x-1
We move all terms to the left:
3(x-1)-2(2x+1)-(8(x-1)=0
We multiply parentheses
3x-4x-(8(x-1)-3-2=0
We add all the numbers together, and all the variables
-1x-(8(x-1)-3-2=0
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