3(x-1)-2(2x+1)=8(x-2)

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Solution for 3(x-1)-2(2x+1)=8(x-2) equation: 



3(x-1)-2(2x+1)=8(x-2)

We move all terms to the left:

3(x-1)-2(2x+1)-(8(x-2))=0

We multiply parentheses

3x-4x-(8(x-2))-3-2=0



We calculate terms in parentheses: -(8(x-2)), so:

8(x-2)

We multiply parentheses

8x-16

Back to the equation:

-(8x-16)



We add all the numbers together, and all the variables

-1x-(8x-16)-5=0

We get rid of parentheses

-1x-8x+16-5=0

We add all the numbers together, and all the variables

-9x+11=0

We move all terms containing x to the left, all other terms to the right

-9x=-11

x=-11/-9

x=1+2/9

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