3(x-1)-2(4x-5)+4(1-x)=20

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Solution for 3(x-1)-2(4x-5)+4(1-x)=20 equation: 



3(x-1)-2(4x-5)+4(1-x)=20

We move all terms to the left:

3(x-1)-2(4x-5)+4(1-x)-(20)=0

We add all the numbers together, and all the variables

3(x-1)-2(4x-5)+4(-1x+1)-20=0

We multiply parentheses

3x-8x-4x-3+10+4-20=0

We add all the numbers together, and all the variables

-9x-9=0

We move all terms containing x to the left, all other terms to the right

-9x=9

x=9/-9

x=-1

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