3(x-1)-2(x+1)=3(x-1)

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Solution for 3(x-1)-2(x+1)=3(x-1) equation: 



3(x-1)-2(x+1)=3(x-1)

We move all terms to the left:

3(x-1)-2(x+1)-(3(x-1))=0

We multiply parentheses

3x-2x-(3(x-1))-3-2=0



We calculate terms in parentheses: -(3(x-1)), so:

3(x-1)

We multiply parentheses

3x-3

Back to the equation:

-(3x-3)



We add all the numbers together, and all the variables

x-(3x-3)-5=0

We get rid of parentheses

x-3x+3-5=0

We add all the numbers together, and all the variables

-2x-2=0

We move all terms containing x to the left, all other terms to the right

-2x=2

x=2/-2

x=-1

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