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3(x-1)-2(x+3)=6-(2x+3)
We move all terms to the left:
3(x-1)-2(x+3)-(6-(2x+3))=0
We multiply parentheses
3x-2x-(6-(2x+3))-3-6=0
We calculate terms in parentheses: -(6-(2x+3)), so:We add all the numbers together, and all the variables
6-(2x+3)
determiningTheFunctionDomain -(2x+3)+6
We get rid of parentheses
-2x-3+6
We add all the numbers together, and all the variables
-2x+3
Back to the equation:
-(-2x+3)
x-(-2x+3)-9=0
We get rid of parentheses
x+2x-3-9=0
We add all the numbers together, and all the variables
3x-12=0
We move all terms containing x to the left, all other terms to the right
3x=12
x=12/3
x=4
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