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3(x-1)-3=5x-2(3+x)
We move all terms to the left:
3(x-1)-3-(5x-2(3+x))=0
We add all the numbers together, and all the variables
3(x-1)-(5x-2(x+3))-3=0
We multiply parentheses
3x-(5x-2(x+3))-3-3=0
We calculate terms in parentheses: -(5x-2(x+3)), so:We add all the numbers together, and all the variables
5x-2(x+3)
We multiply parentheses
5x-2x-6
We add all the numbers together, and all the variables
3x-6
Back to the equation:
-(3x-6)
3x-(3x-6)-6=0
We get rid of parentheses
3x-3x+6-6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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