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3(x-1)-8(x+4)=1-3x+x-6
We move all terms to the left:
3(x-1)-8(x+4)-(1-3x+x-6)=0
We add all the numbers together, and all the variables
3(x-1)-8(x+4)-(-2x-5)=0
We multiply parentheses
3x-8x-(-2x-5)-3-32=0
We get rid of parentheses
3x-8x+2x+5-3-32=0
We add all the numbers together, and all the variables
-3x-30=0
We move all terms containing x to the left, all other terms to the right
-3x=30
x=30/-3
x=-10
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