3(x-1)-8=(1+x)+5

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Solution for 3(x-1)-8=(1+x)+5 equation: 



3(x-1)-8=(1+x)+5

We move all terms to the left:

3(x-1)-8-((1+x)+5)=0

We add all the numbers together, and all the variables

3(x-1)-((x+1)+5)-8=0

We multiply parentheses

3x-((x+1)+5)-3-8=0



We calculate terms in parentheses: -((x+1)+5), so:

(x+1)+5

We get rid of parentheses

x+1+5

We add all the numbers together, and all the variables

x+6

Back to the equation:

-(x+6)



We add all the numbers together, and all the variables

3x-(x+6)-11=0

We get rid of parentheses

3x-x-6-11=0

We add all the numbers together, and all the variables

2x-17=0

We move all terms containing x to the left, all other terms to the right

2x=17

x=17/2

x=8+1/2

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