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3(x-1)-8=10-3(x-4)
We move all terms to the left:
3(x-1)-8-(10-3(x-4))=0
We multiply parentheses
3x-(10-3(x-4))-3-8=0
We calculate terms in parentheses: -(10-3(x-4)), so:We add all the numbers together, and all the variables
10-3(x-4)
determiningTheFunctionDomain -3(x-4)+10
We multiply parentheses
-3x+12+10
We add all the numbers together, and all the variables
-3x+22
Back to the equation:
-(-3x+22)
3x-(-3x+22)-11=0
We get rid of parentheses
3x+3x-22-11=0
We add all the numbers together, and all the variables
6x-33=0
We move all terms containing x to the left, all other terms to the right
6x=33
x=33/6
x=5+1/2
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