3(x-1)-8=4(1+4x)+5

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Solution for 3(x-1)-8=4(1+4x)+5 equation: 



3(x-1)-8=4(1+4x)+5

We move all terms to the left:

3(x-1)-8-(4(1+4x)+5)=0

We add all the numbers together, and all the variables

3(x-1)-(4(4x+1)+5)-8=0

We multiply parentheses

3x-(4(4x+1)+5)-3-8=0



We calculate terms in parentheses: -(4(4x+1)+5), so:

4(4x+1)+5

We multiply parentheses

16x+4+5

We add all the numbers together, and all the variables

16x+9

Back to the equation:

-(16x+9)



We add all the numbers together, and all the variables

3x-(16x+9)-11=0

We get rid of parentheses

3x-16x-9-11=0

We add all the numbers together, and all the variables

-13x-20=0

We move all terms containing x to the left, all other terms to the right

-13x=20

x=20/-13

x=-1+7/13

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