3(x-1)-8=4(1+x)-5

Solution for 3(x-1)-8=4(1+x)-5 equation:

3(x-1)-8=4(1+x)-5

We move all terms to the left:

3(x-1)-8-(4(1+x)-5)=0

We add all the numbers together, and all the variables

3(x-1)-(4(x+1)-5)-8=0

We multiply parentheses

3x-(4(x+1)-5)-3-8=0


We calculate terms in parentheses: -(4(x+1)-5), so:

4(x+1)-5

We multiply parentheses

4x+4-5

We add all the numbers together, and all the variables

4x-1

Back to the equation:

-(4x-1)


We add all the numbers together, and all the variables

3x-(4x-1)-11=0

We get rid of parentheses

3x-4x+1-11=0

We add all the numbers together, and all the variables

-1x-10=0

We move all terms containing x to the left, all other terms to the right

-x=10

x=10/-1

x=-10