3(x-1)-8=4(1+x0)+5

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Solution for 3(x-1)-8=4(1+x0)+5 equation: 



3(x-1)-8=4(1+x0)+5

We move all terms to the left:

3(x-1)-8-(4(1+x0)+5)=0

We add all the numbers together, and all the variables

3(x-1)-(4(x+1)+5)-8=0

We multiply parentheses

3x-(4(x+1)+5)-3-8=0



We calculate terms in parentheses: -(4(x+1)+5), so:

4(x+1)+5

We multiply parentheses

4x+4+5

We add all the numbers together, and all the variables

4x+9

Back to the equation:

-(4x+9)



We add all the numbers together, and all the variables

3x-(4x+9)-11=0

We get rid of parentheses

3x-4x-9-11=0

We add all the numbers together, and all the variables

-1x-20=0

We move all terms containing x to the left, all other terms to the right

-x=20

x=20/-1

x=-20

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