3(x-1)-8=4(1-x)+5

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Solution for 3(x-1)-8=4(1-x)+5 equation: 



3(x-1)-8=4(1-x)+5

We move all terms to the left:

3(x-1)-8-(4(1-x)+5)=0

We add all the numbers together, and all the variables

3(x-1)-(4(-1x+1)+5)-8=0

We multiply parentheses

3x-(4(-1x+1)+5)-3-8=0



We calculate terms in parentheses: -(4(-1x+1)+5), so:

4(-1x+1)+5

We multiply parentheses

-4x+4+5

We add all the numbers together, and all the variables

-4x+9

Back to the equation:

-(-4x+9)



We add all the numbers together, and all the variables

3x-(-4x+9)-11=0

We get rid of parentheses

3x+4x-9-11=0

We add all the numbers together, and all the variables

7x-20=0

We move all terms containing x to the left, all other terms to the right

7x=20

x=20/7

x=2+6/7

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