3(x-1)-8=4(x+1)+5

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Solution for 3(x-1)-8=4(x+1)+5 equation:



3(x-1)-8=4(x+1)+5
We move all terms to the left:
3(x-1)-8-(4(x+1)+5)=0
We multiply parentheses
3x-(4(x+1)+5)-3-8=0
We calculate terms in parentheses: -(4(x+1)+5), so:
4(x+1)+5
We multiply parentheses
4x+4+5
We add all the numbers together, and all the variables
4x+9
Back to the equation:
-(4x+9)
We add all the numbers together, and all the variables
3x-(4x+9)-11=0
We get rid of parentheses
3x-4x-9-11=0
We add all the numbers together, and all the variables
-1x-20=0
We move all terms containing x to the left, all other terms to the right
-x=20
x=20/-1
x=-20

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