3(x-1)-8=4+(1+x)+5

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Solution for 3(x-1)-8=4+(1+x)+5 equation: 



3(x-1)-8=4+(1+x)+5

We move all terms to the left:

3(x-1)-8-(4+(1+x)+5)=0

We add all the numbers together, and all the variables

3(x-1)-(4+(x+1)+5)-8=0

We multiply parentheses

3x-(4+(x+1)+5)-3-8=0



We calculate terms in parentheses: -(4+(x+1)+5), so:

4+(x+1)+5

determiningTheFunctionDomain
(x+1)+4+5

We add all the numbers together, and all the variables

(x+1)+9

We get rid of parentheses

x+1+9

We add all the numbers together, and all the variables

x+10

Back to the equation:

-(x+10)



We add all the numbers together, and all the variables

3x-(x+10)-11=0

We get rid of parentheses

3x-x-10-11=0

We add all the numbers together, and all the variables

2x-21=0

We move all terms containing x to the left, all other terms to the right

2x=21

x=21/2

x=10+1/2

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