3(x-1)/4=3(x+2)/7

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Solution for 3(x-1)/4=3(x+2)/7 equation: 



3(x-1)/4=3(x+2)/7

We move all terms to the left:

3(x-1)/4-(3(x+2)/7)=0

We calculate fractions


3x/()+(-(3(x+2)*4)/()=0



We calculate terms in parentheses: +(-(3(x+2)*4)/(), so:

-(3(x+2)*4)/(

We multiply all the terms by the denominator


-(3(x+2)*4)



We calculate terms in parentheses: -(3(x+2)*4), so:

3(x+2)*4

We multiply parentheses

12x+24

Back to the equation:

-(12x+24)



We get rid of parentheses

-12x-24

Back to the equation:

+(-12x-24)



We get rid of parentheses

3x/()-12x-24=0

We multiply all the terms by the denominator


3x-12x*()-24*()=0

We add all the numbers together, and all the variables

3x-12x*()=0

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