3(x-1)/5=3(x+1)/7

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Solution for 3(x-1)/5=3(x+1)/7 equation: 



3(x-1)/5=3(x+1)/7

We move all terms to the left:

3(x-1)/5-(3(x+1)/7)=0

We calculate fractions


3x/()+(-(3(x+1)*5)/()=0



We calculate terms in parentheses: +(-(3(x+1)*5)/(), so:

-(3(x+1)*5)/(

We multiply all the terms by the denominator


-(3(x+1)*5)



We calculate terms in parentheses: -(3(x+1)*5), so:

3(x+1)*5

We multiply parentheses

15x+15

Back to the equation:

-(15x+15)



We get rid of parentheses

-15x-15

Back to the equation:

+(-15x-15)



We get rid of parentheses

3x/()-15x-15=0

We multiply all the terms by the denominator


3x-15x*()-15*()=0

We add all the numbers together, and all the variables

3x-15x*()=0

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