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3(x-1)/5=3(x+3)/9
We move all terms to the left:
3(x-1)/5-(3(x+3)/9)=0
We calculate fractions
3x/()+(-(3(x+3)*5)/()=0
We calculate terms in parentheses: +(-(3(x+3)*5)/(), so:We get rid of parentheses
-(3(x+3)*5)/(
We multiply all the terms by the denominator
-(3(x+3)*5)
We calculate terms in parentheses: -(3(x+3)*5), so:We get rid of parentheses
3(x+3)*5
We multiply parentheses
15x+45
Back to the equation:
-(15x+45)
-15x-45
Back to the equation:
+(-15x-45)
3x/()-15x-45=0
We multiply all the terms by the denominator
3x-15x*()-45*()=0
We add all the numbers together, and all the variables
3x-15x*()=0
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