3(x-1)=-9(x+3)+45

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Solution for 3(x-1)=-9(x+3)+45 equation: 



3(x-1)=-9(x+3)+45

We move all terms to the left:

3(x-1)-(-9(x+3)+45)=0

We multiply parentheses

3x-(-9(x+3)+45)-3=0



We calculate terms in parentheses: -(-9(x+3)+45), so:

-9(x+3)+45

We multiply parentheses

-9x-27+45

We add all the numbers together, and all the variables

-9x+18

Back to the equation:

-(-9x+18)



We get rid of parentheses

3x+9x-18-3=0

We add all the numbers together, and all the variables

12x-21=0

We move all terms containing x to the left, all other terms to the right

12x=21

x=21/12

x=1+3/4

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