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3(x-1)=2(6-x)
We move all terms to the left:
3(x-1)-(2(6-x))=0
We add all the numbers together, and all the variables
3(x-1)-(2(-1x+6))=0
We multiply parentheses
3x-(2(-1x+6))-3=0
We calculate terms in parentheses: -(2(-1x+6)), so:We get rid of parentheses
2(-1x+6)
We multiply parentheses
-2x+12
Back to the equation:
-(-2x+12)
3x+2x-12-3=0
We add all the numbers together, and all the variables
5x-15=0
We move all terms containing x to the left, all other terms to the right
5x=15
x=15/5
x=3
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