3(x-1)=2(x-4)+8

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Solution for 3(x-1)=2(x-4)+8 equation: 



3(x-1)=2(x-4)+8

We move all terms to the left:

3(x-1)-(2(x-4)+8)=0

We multiply parentheses

3x-(2(x-4)+8)-3=0



We calculate terms in parentheses: -(2(x-4)+8), so:

2(x-4)+8

We multiply parentheses

2x-8+8

We add all the numbers together, and all the variables

2x

Back to the equation:

-(2x)



We add all the numbers together, and all the variables

x-3=0

We move all terms containing x to the left, all other terms to the right

x=3

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