3(x-1)=3x+1-2(-8x-1)

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Solution for 3(x-1)=3x+1-2(-8x-1) equation: 



3(x-1)=3x+1-2(-8x-1)

We move all terms to the left:

3(x-1)-(3x+1-2(-8x-1))=0

We multiply parentheses

3x-(3x+1-2(-8x-1))-3=0



We calculate terms in parentheses: -(3x+1-2(-8x-1)), so:

3x+1-2(-8x-1)

determiningTheFunctionDomain
3x-2(-8x-1)+1

We multiply parentheses

3x+16x+2+1

We add all the numbers together, and all the variables

19x+3

Back to the equation:

-(19x+3)



We get rid of parentheses

3x-19x-3-3=0

We add all the numbers together, and all the variables

-16x-6=0

We move all terms containing x to the left, all other terms to the right

-16x=6

x=6/-16

x=-3/8

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