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3(x-1)=4(2x+1)
We move all terms to the left:
3(x-1)-(4(2x+1))=0
We multiply parentheses
3x-(4(2x+1))-3=0
We calculate terms in parentheses: -(4(2x+1)), so:We get rid of parentheses
4(2x+1)
We multiply parentheses
8x+4
Back to the equation:
-(8x+4)
3x-8x-4-3=0
We add all the numbers together, and all the variables
-5x-7=0
We move all terms containing x to the left, all other terms to the right
-5x=7
x=7/-5
x=-1+2/5
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