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3(x-1)=5(x+3)-5
We move all terms to the left:
3(x-1)-(5(x+3)-5)=0
We multiply parentheses
3x-(5(x+3)-5)-3=0
We calculate terms in parentheses: -(5(x+3)-5), so:We get rid of parentheses
5(x+3)-5
We multiply parentheses
5x+15-5
We add all the numbers together, and all the variables
5x+10
Back to the equation:
-(5x+10)
3x-5x-10-3=0
We add all the numbers together, and all the variables
-2x-13=0
We move all terms containing x to the left, all other terms to the right
-2x=13
x=13/-2
x=-6+1/2
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