3(x-1)=6/2x+2

Solution for 3(x-1)=6/2x+2 equation:

3(x-1)=6/2x+2

We move all terms to the left:

3(x-1)-(6/2x+2)=0


Domain of the equation: 2x+2)!=0

x∈R


We multiply parentheses

3x-(6/2x+2)-3=0

We get rid of parentheses

3x-6/2x-2-3=0

We multiply all the terms by the denominator


3x*2x-2*2x-3*2x-6=0

Wy multiply elements

6x^2-4x-6x-6=0

We add all the numbers together, and all the variables

6x^2-10x-6=0

a = 6; b = -10; c = -6;
Δ = b2-4ac
Δ = -102-4·6·(-6)
Δ = 244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{244}=\sqrt{4*61}=\sqrt{4}*\sqrt{61}=2\sqrt{61}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{61}}{2*6}=\frac{10-2\sqrt{61}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{61}}{2*6}=\frac{10+2\sqrt{61}}{12}
$