3(x-1)=6x+2(1-x)

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Solution for 3(x-1)=6x+2(1-x) equation: 



3(x-1)=6x+2(1-x)

We move all terms to the left:

3(x-1)-(6x+2(1-x))=0

We add all the numbers together, and all the variables

3(x-1)-(6x+2(-1x+1))=0

We multiply parentheses

3x-(6x+2(-1x+1))-3=0



We calculate terms in parentheses: -(6x+2(-1x+1)), so:

6x+2(-1x+1)

We multiply parentheses

6x-2x+2

We add all the numbers together, and all the variables

4x+2

Back to the equation:

-(4x+2)



We get rid of parentheses

3x-4x-2-3=0

We add all the numbers together, and all the variables

-1x-5=0

We move all terms containing x to the left, all other terms to the right

-x=5

x=5/-1

x=-5

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