3(x-1)=x+5-2(-8x-4)

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Solution for 3(x-1)=x+5-2(-8x-4) equation: 



3(x-1)=x+5-2(-8x-4)

We move all terms to the left:

3(x-1)-(x+5-2(-8x-4))=0

We multiply parentheses

3x-(x+5-2(-8x-4))-3=0



We calculate terms in parentheses: -(x+5-2(-8x-4)), so:

x+5-2(-8x-4)

determiningTheFunctionDomain
x-2(-8x-4)+5

We multiply parentheses

x+16x+8+5

We add all the numbers together, and all the variables

17x+13

Back to the equation:

-(17x+13)



We get rid of parentheses

3x-17x-13-3=0

We add all the numbers together, and all the variables

-14x-16=0

We move all terms containing x to the left, all other terms to the right

-14x=16

x=16/-14

x=-1+1/7

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