3(x-10)+2(x+1)=127

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Solution for 3(x-10)+2(x+1)=127 equation:


Simplifying
3(x + -10) + 2(x + 1) = 127

Reorder the terms:
3(-10 + x) + 2(x + 1) = 127
(-10 * 3 + x * 3) + 2(x + 1) = 127
(-30 + 3x) + 2(x + 1) = 127

Reorder the terms:
-30 + 3x + 2(1 + x) = 127
-30 + 3x + (1 * 2 + x * 2) = 127
-30 + 3x + (2 + 2x) = 127

Reorder the terms:
-30 + 2 + 3x + 2x = 127

Combine like terms: -30 + 2 = -28
-28 + 3x + 2x = 127

Combine like terms: 3x + 2x = 5x
-28 + 5x = 127

Solving
-28 + 5x = 127

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '28' to each side of the equation.
-28 + 28 + 5x = 127 + 28

Combine like terms: -28 + 28 = 0
0 + 5x = 127 + 28
5x = 127 + 28

Combine like terms: 127 + 28 = 155
5x = 155

Divide each side by '5'.
x = 31

Simplifying
x = 31

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