3(x-10)=2(4x+35)

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Solution for 3(x-10)=2(4x+35) equation: 



3(x-10)=2(4x+35)

We move all terms to the left:

3(x-10)-(2(4x+35))=0

We multiply parentheses

3x-(2(4x+35))-30=0



We calculate terms in parentheses: -(2(4x+35)), so:

2(4x+35)

We multiply parentheses

8x+70

Back to the equation:

-(8x+70)



We get rid of parentheses

3x-8x-70-30=0

We add all the numbers together, and all the variables

-5x-100=0

We move all terms containing x to the left, all other terms to the right

-5x=100

x=100/-5

x=-20

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