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3(x-10)=2(4x+35)
We move all terms to the left:
3(x-10)-(2(4x+35))=0
We multiply parentheses
3x-(2(4x+35))-30=0
We calculate terms in parentheses: -(2(4x+35)), so:We get rid of parentheses
2(4x+35)
We multiply parentheses
8x+70
Back to the equation:
-(8x+70)
3x-8x-70-30=0
We add all the numbers together, and all the variables
-5x-100=0
We move all terms containing x to the left, all other terms to the right
-5x=100
x=100/-5
x=-20
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